which term of the AP 92, 88,84, 80 is 0?
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T=a+(n-1)d
a=92
d=88-92=>-4
T=0
0=92+(n-1)-4
-92=-4n+4
-92-4=-4n
-96=-4n
28=n
28th term is 0
a=92
d=88-92=>-4
T=0
0=92+(n-1)-4
-92=-4n+4
-92-4=-4n
-96=-4n
28=n
28th term is 0
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