Given 1 dm3 of 0.15 M HCL and 1 dm3 of 0.4 M HCL what is maximum volume of 0.15 M HCL which can be made by directly mixing the two solutions without adding water
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Let V = volume of final mixture which makes 0.2M HCl.
V*0.2 = 1*0.15 + (V-1)*0.3
0.2V = 0.15 +0.3V -0.3
0.2V = -0.15 + 0.3V
-0.1V = -0.15
V = 1.5 liters of 0.2M HCl
Notice that chloride is Cl, not CL.
V*0.2 = 1*0.15 + (V-1)*0.3
0.2V = 0.15 +0.3V -0.3
0.2V = -0.15 + 0.3V
-0.1V = -0.15
V = 1.5 liters of 0.2M HCl
Notice that chloride is Cl, not CL.
priyanshdutt09:
Why can
why can't we do like this 0.15 *1. +. 0.4*1. =. 0.15*v
0.15*1/2 + 0.4*1/2 = 0.15 V
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