given 13 sin A = 12 find sec A - tan A
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Step-by-step explanation:
sinA=12/13
refer above figure
AC²+BC²=AB²
AC²+144a²=169a²
AC²=25a²
AC=5a
secA=AB/AC
=13/5
tanA=BC/AC
=12/5
secA-tanA=13/5-12/5
=1/5
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