Given 15 cot A = 8, find sin A
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2
Answer:
cot A=8/15 SO THAT USING PYTHAGORAS THEOREM AB^2=BC^2+AC^2
AB^2=15^2+8^2
AB^2=225+64
AB^2 =289
AB=√289
AB=17
Answered by
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15 cot A=8
cot A= 8/15
Cot A = Base/Perpendicular
so Hypotonuse= 15²+8²
225+264= 289
hypotunuse=17
Sin A = 15/17
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