Question

given 15 cot A=8,find sinA and sec A​

Answer 1

Answer below:

Sin A = $\frac{15}{17}$=15/17 and Sec A = $\frac{17}{8}$=17/8

Explanation:

Given,

15 cot A =8 => cot A = 8/15=$\frac{8}{15}$

Also, cot A =  Base/Perpendicular

By Pythagoras' Theorem, we have

$Hypotenuse^{2}$ = $Base^{2}$+$Perpendicular^{2}$

$Hypotenuse^{2}$  = $8^{2}$+$15^{2}$

Hypotenuse = $\sqrt{64+225}$

Hypotenuse = $\sqrt{289}$

Hypotenuse = 17

So, Sin A = $\frac{Perpendicular}{Hypotenuse}$=$\frac{15}{17}$

Sec A = $\frac{Hypotenuse}{Base}$=$\frac{17}{8}$

Hope it helps.....

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Answer 2

Answer:

sec 17/8 is ur ans bro

mark as brain list