Question

given 15 cot A =8 find the other trigomnometric ratios of angleA

Answer 1

15 cotA=8
cotA=8/15
cotA=adjacent side /opposite side
therefore adjacent side=8
opposite side=15 
by pythogorous theorem 
hypotenus²=15²+8²
hypotenus²=225+64
hypotenus=√289
hypotenus=17
tanA=opp/adj
tanA=15/8
sinA=opp/hyp
sinA=15/17
cosA=adj/hyp
cosA=8/17
secA=hyp/adj
secA=17/8
cosecA=hyp/opp
cosecA=17/15

Answer 2

Answer and explanation:

Given : $15\cot A=8$

To find : The other trigonometric ratios of angle A ?

Solution :

We know that,

$\cot A=\frac{B}{P}$

Where, B is the base and P is the perpendicular

$\cot A=\frac{8}{15}$

Now, We find hypotenuse

$H^2=P^2+B^2$

$H^2=(15)^2+(8)^2$

$H^2=225+64$

$H=\sqrt{289}$

$H=17$

So, H=17 , B=8 , P=15

$\sin A=\frac{P}{H}=\frac{15}{17}$

$\cos A=\frac{B}{H}=\frac{8}{17}$

$\csc A=\frac{H}{P}=\frac{17}{15}$

$\sec A=\frac{H}{B}=\frac{17}{8}$

$\tan A=\frac{P}{B}=\frac{15}{8}$