Question

Given 15Cot A=8,find Sec A ?
Solve​

Answer 1

Answer:

Hello

Explanation:

=

15Cot A=8,

Therefore, Cot A=8/15

By Pythagoras theorem

We can find third side

( Hypo) sq=(S1) sq+(S2) sq

${hypo}^{2} = {8}^{2} + {15}^{2} </em></p><p><em> \\ \: \: \: \: \: \: \: \: \: \: \: = 64 + 225 \\</em></p><p><em> hypo = 17$

Sec A = $sec \: a = \frac{hypotenuse}{ \: adjacent}$$= > \frac{17}{8}$]

Answer 2

Answer:

secA = 17/8

Explanation:

15 cot A =8

cot A= 8/15 

cot A = 8/15  = base/height

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Let height be 15x and base be 8x

By Pythagoras Theorem,

(15x)^2 + (8x)^2 = hypotenuse^2

(225 + 64)x^2  = hypotenuse^2

289x^2 = hypotenuse^2

17x  = hypotenuse

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Now,

sec A = hypotenuse/base

Sec A = 17/8

Hope this will help you

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