Question

What is the minimum energy required to launch a satellite of mass m from the surface of a planet of mass M and radius R in a circular orbit at an altitude of 2R?​

Answer 1

Answer:

hiii

your answer is here !

Explanation:

In circular orbit of a satellite, potential energy = −2 × Kinetic Energy = −mV^2.

So, just to escape from the gravitational pull, its total mechanical energy should be zero.

Therefore its kinetic energy should be mV^2.

follow me ! ✌️✌️✌️✌️

Answer 2

Answer:

hlo mate here is ur answer

Explanation:

hope it helps u dear..