Given 2 sides of a triangle find the angle between them
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Consider the following triangle △ABC, the poly 1 below, with sides AB¯¯¯¯¯¯¯¯=c and AC¯¯¯¯¯¯¯¯=b known. Further the angle between them, α is known.
Then, the law of cosines tell you that
a2=b2+c2−2bccosα
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"SAS" is when we know two sides and the angle between them. use The Law of Cosines to calculate the unknown side, then use The Law of Sines to find the smaller of the other two angles, and then use the three angles add to 180° to find the last angle.
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In this triangle we know:
- angle A = 49°
- b = 5.
- and c = 7.
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