Question

Given 2i-2j - 3kand B = 4i-2j+ 6k. Calculate the angle made by (A + B) with x-axis.​

Answer 1

Answer:

note check this attachment

Answer 2

ANSWER...

$vector (1) = 2i - 2j - 3k \\ \\ vector(2) = 4i - 2j + 6k \\ \\ resultant \: vector = vector(1) + vector(2) \\ \\ resultant \: vector = (2 + 4)i - (2 + 2)j + (6 - 3)k \\ \\ resultant \: vector = 6i - 4j + 3k \\ \\ |resultant \:vector | = \sqrt{ ({6})^{2} + ({4})^{2} + ({3})^{2} } \\ \\ |resultant \: vector| = \sqrt{36 + 16 + 9} \\ \\ |resultant \: vector| = \sqrt{61} \\ \\ let \: the \: angle \: between \: x \: axis \: and \\ \: the \: resultant \: vector \: be \: \alpha \: then \\ \\ |resultant \: vector| .i \cos \alpha = resultant \: vector.i \\ \\ \sqrt{61} .1. \cos \alpha = (6i - 4j + 3k)(i + 0j + 0k) \\ \\ \cos \alpha = \frac{6}{ \sqrt{61} }$