given 58 grams of butane (C4H10) molecules:(a) what is the molecular mass of butane? (b) how many moles of C4H10 are present?(c) how many molecules of C4H10 are present?(d) what is the total number of atoms in each molecules of C4H10 ?(e) what is the total number of moles of atoms in each mole of C4H10 molecules? (f) what is the total number of moles of atoms in the sample?(g) what is the total number of atoms in the sample?
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c=12;H=1
10 +48 is 58
10 +48 is 58
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answers. a) 58gm, b)1 mole, c)avogadro number molecules, d)10 into avogadro numbers,
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