Math, asked by junaidabedin07, 7 months ago

Given (8/27)^x-1 = (9/4)^2x+1. ;find the value of x

Answers

Answered by praneetha19
0

Step-by-step explanation:

(8÷27)x-1=(9/4)2x+1

(8/27)x-(9/4)2x=1+1=2

(8/27)X-(9/2)X=2

(16/54)X-(243/54)X=2

-227/54x=2

X=-(2×54)/227= -0•475

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