given A=0.3 +0.4j-ck. caluclated the value of c if A is a unit vectors
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1
magnitude is 1
so 0.3^2+ 0.4^2 + c^2=1
c^2= 1-0.25=0.75
C=√0.75
so 0.3^2+ 0.4^2 + c^2=1
c^2= 1-0.25=0.75
C=√0.75
jamal4:
How i=2
which i
its wholesquare
Answered by
0
given a is a unit vector
so |A|=1
so under root of (0.3)*2(0.4)*2+c*2=1
so |A|=1
so under root of (0.3)*2(0.4)*2+c*2=1
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