Math, asked by sudipto39, 10 months ago

given (a-1/a)^2=3 then prove that (a^6+1/a^6)=110​

Answers

Answered by Anonymous
0

Step-by-step explanation:

(a-1/a)² = 3

a² + 1/a² - 2 = 3

a² + 1/a² = 5

घन करने पर

(a² + 1/a²)³ = (5)³

a^6 + 1/a^6 + 3*1(5) = 125

a^6 + 1/a^6 = 125-15

= 110

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