Question

Given A (-2, 3) and AB = 10 units . if the ordinate of B is 9, find abscissa of B

Answer 1

Step-by-step explanation:

Please refer the attachment

Answer 2

Answer:

Abscissa of B = 6 units

Step-by-step explanation:

Coordinate system:

• Coordinates are a collection of numbers that aid in displaying a point's precise location on the coordinate plane.
• Coordinate plane in two dimension is denoted as (x,y).
• x-coordinate is called as abscissa and y-coordinate is called as ordinate.

Distance between two points:

• Let A = (x₁,y₁) and B = (x₂,y₂) are two points then the distance between AB  is given by the formula

                 $\sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y_{1})^{2}}$

Given, point A = (-2,3) = (x₁,y₁)

           ordinate of B is 9

 Let the abscissa of B be x then B = (x,9) = (x₂,y₂)

   Distance between AB = $\sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y_{1})^{2}}$

       Given distance between AB = 10 units

              $\sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y_{1})^{2}}$ = 10

                     $\sqrt{(x+2 )^{2} +(9-3)^{2}}$ = 10

                                (x+2)²+(9-3)²  = (10)²

                                       (x+2)²+6² = 100

                                             (x+2)² = 100-36

                                              (x+2)² = 64

                                                (x+2) = $\sqrt{64}$

                                                  x+2 = 8

                                                      x = 8-2

                                                       x = 6

                    Hence, abscissa of B = 6 units

       

  Know more about Coordinates:

  brainly.in/question/4384478

  brainly.in/question/21523537