prove that root 11 is irrational
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Let √11 be rational. Then
√11 = p/q, where p and q are integers, q≠0 and p and q are co-primes.
Squaring both sides,
(√11)² = (p/q)²
11 = p²/q²
p² = 11q²
This means that p is a multiple of 11.
Let 11a = p
⇒ 121a² = 11q²
⇒ 11a² = q²
This means q is also a multiple of 11.
p and q both are multiples of 11. This means that they are not co-primes.
So, our supposition is wrong. Thus, √11 is irrational.
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