Math, asked by preeti1257, 11 months ago

please solve all questions with step by step explanation


1. Prakash earn rs. 30000 per month and
his wife Seema earns rs.12000 per month if Prakash saves rs. 12000 per month and Seema saves 6000 per month how much amount of money will both save after 1 year ?

2. a rope of length 10 metre has been divided into 8 pieces of the same length what is the length of each piece ?​

Answers

Answered by virag28
1

Adding savings of prakash and seema it will be rs 216000 of 1 year

Attachments:
Answered by Anonymous
4

Hi !!!

1. Prashanth Earns per year

=30,000x12=Rs.3,60,000

Seema Earns per year =12000x12=2,40,000

Both total income = 3,60,000+2,40,000=Rs.6,00,000

Prashanth saves per year = 12,000x12=Rs.2,40,000

Seema saves per year = 6000x12=Rs.72000

Both saves together = 2,40,000+72000= Rs.3,12,000

The left over money with them = 6,00,000-3,12,000= 2,88,000

2. Length of rope is = 10 m

It is divided into = 8 parts

Length of each piece = 10÷8

It is 1.25 m !!!

Are you happy with these answers ??

If yes , Mark as brain list and

rock on !!


preeti1257: it helps me a lot
Anonymous: ok
preeti1257: hi
Similar questions