please solve all questions with step by step explanation
1. Prakash earn rs. 30000 per month and
his wife Seema earns rs.12000 per month if Prakash saves rs. 12000 per month and Seema saves 6000 per month how much amount of money will both save after 1 year ?
2. a rope of length 10 metre has been divided into 8 pieces of the same length what is the length of each piece ?
Answers
Answered by
1
Adding savings of prakash and seema it will be rs 216000 of 1 year
Attachments:
Answered by
4
Hi !!!
1. Prashanth Earns per year
=30,000x12=Rs.3,60,000
Seema Earns per year =12000x12=2,40,000
Both total income = 3,60,000+2,40,000=Rs.6,00,000
Prashanth saves per year = 12,000x12=Rs.2,40,000
Seema saves per year = 6000x12=Rs.72000
Both saves together = 2,40,000+72000= Rs.3,12,000
The left over money with them = 6,00,000-3,12,000= 2,88,000
2. Length of rope is = 10 m
It is divided into = 8 parts
Length of each piece = 10÷8
It is 1.25 m !!!
Are you happy with these answers ??
If yes , Mark as brain list and
rock on !!
preeti1257:
it helps me a lot
Similar questions