Given A=(3,0) and B=(0,b-2). Find b if AB =5
Answers
Answered by
3
Answer:
b=6 or b= -2
Step-by-step explanation:
using distance formula
25=√(0-3)^2 +(b-2-0)^2
taking Square on both sides
equation becomes
b^2-4b-12=0
by factorisation
b^2-6b+2b-12=0
b(b-6)+2(b-6)=0
(b-6)(b+2)=0
b=6 or b=-2
Answered by
3
Answer:
distance between any two points is given by Formula
distance²= (x1 -x2 )² +(y1 -y2 )²
A =(3,0) means
x1= 3 and y1 =0
B= (0, b-2) means
x2= 0 and y2= b-2
AB =5
5² = (3 -0)² +[ 0- (b-2)]²
25= 9 +b² -4b +4
b² -4b- 12=0
By solving this equation we get,
b = -2 , 6
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