given a=7,a13 = 35, find d and S13
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Step-by-step explanation:
a13=35
we know that an=a+(n-1)d
therefore,
a+(13-1)d=35
a+12d=35
And a=7
7+12d=35
12d=35-7
12d=28
d=28/12
d=7/3
S13=13/2[2a+(13-1)d]
putting the value of d and a in the equation
S13= 13/2[2(7) + 12(7/3)]
S13=13/2[14+28]
S13=13/2 × 42
S13=13×21
S13=273
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