Question

given a and b are rational number. find and b if: (i) 3-√5/3+2√5= -19/11+a√5​

Answer 1

Answer:

3-root5(11+aroot5)=-19(3+2root5)

3(11+aroot5)-root5(11+aroot5)=-57-38root5

33+3aroot5-11root5-a5+57+38root

90+3aroot5-11root5-5a+38root5

90+27root5-5a+3root5a)

90+root5(27+3a)-5a

-5a+root5(27+3a)+90=0

5a-root5(27+3a)-90=0

a=-27/3=-9