Math, asked by pushpakrathod, 9 hours ago

) Given a, b, c, d, e are natural numbers such that a + b = b + c = c + d = d + e = 4021 and a + b + c + d + e = 11063. Then the numerical value of (a – d) is​

Answers

Answered by dudinikhil3079
0

Answer:

Step-by-step explanation:

a=C−2D

b=C−D

c=C

d=C+D

e=C+2D

Then,

a+b+c+d+e=5C=α

3

....(i)

b+c+d=3C=β

2

=675

c=C=675

Similar questions