Question

Given a chord AB of length 5 cm, of a circle with centre O. OL is perpendicular to chord AB and OL=4 cm. OM is perpendicular to chord CD such that OM=4 cm. Then CM is equal to



a. 4 cm

b. 2.5 cm

c. 5 cm

d. 3 cm

plzz answer me plzz​

Answer 1

Step-by-step explanation:

17 cm. 9.In the given figure, chords AB and CD subtend equal angles each = 70° at the centre O of the circle. OL. AB and AL = 2.5 cm ...

Answer 2

the answer is 4 CM. . because of alternate interior angles.