Given a chord AB of length 5 cm, of a circle with centre O. OL is perpendicular to chord AB and OL=4 cm. OM is perpendicular to chord CD such that OM=4 cm. Then CM is equal to
a. 4 cm
b. 2.5 cm
c. 5 cm
d. 3 cm
plzz answer me plzz
Answers
Answered by
1
Step-by-step explanation:
17 cm. 9.In the given figure, chords AB and CD subtend equal angles each = 70° at the centre O of the circle. OL. AB and AL = 2.5 cm ...
Answered by
2
the answer is 4 CM. . because of alternate interior angles.
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