Given a circle with centre O and radius 4 cm. P be a point such that OP = 5 cm. Find the length of the tangent from P to the circle.
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Answer:
Step-by-step explanation: Solution:
In the attached figure
OA = OB = 5cm [radius of circle]
AB = 5√3 cm [ chord length]
Construction: Draw a perpendicular line OE on chord AB
As we know that perpendicular OE bisect the chord AB,so
Now in Right triangle ∆OEA
Angle OAE =>
we know that √3/2 is value of cos 30°
so,angle OAE = 30°
Thus angle AOE = 60°[ angle sum property of triangle]
By the same way in another triangle ∆OBE
Angle OBE = 30°
So,center angle of the chord is 120°
Now area of the sector OAB
Hope it helps you.
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