Given: A circle with circumference 100 cm and a square inscribed in it.
Find the length of the side of this square.
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506 is the approximate value
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Given data:-
- A circle with circumference 100 cm and a square inscribed in it.
Solution:-
Let, quadrilateral ABCD is a inscribed square.
{We need to find radius ( r ) of circle}
→ Perimeter of circle = 2πr
{From given}
→ 100 = 2 × 22/7 × r
→ 100 = 44/7 × r i.e.
→ r = {100 × 7}/44
→ r = 700/44
→ r = 175/11
→ r = 50.9090 cm (approx)
According to figure AC is diameter.
AO & OC are radius of circle.
We know,
→ Diameter = 2 × radius
→ Diameter = 2 × 15.9090
→ Diameter = 31.818 cm
::Properties of square::
- All side of square are equal in length.
- All angle of square are equal to 90° or they are called as right angle
- Diameter = 31.818 cm of circle is know to be hypotenuse of square according to fingure and Properties of square.
- According to property we can assime that → DC = BC = x
Now, we use Pythagoras theorem to find side of square, so, now from figure
→ (AD)² = (DC)² + (BC)²
→ (31.818)² = (x)² + (x)²
→ 1012.3851 = 2x² i.e.
→ x² = 1012.3851/2
→ x² = 506.1925
→ x = √506.1925
→ x = 22.4987 cm
Hence, the length of side of square is 22.4987 cm.
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