Question

Given a compound that contains 5.93 % Hydrogen, 94.07% Oxygen. What is its empirical formula?

Answer 1

sorry I can't understand this question

Answer 2

$\LARGE\bold{\color{yellow}{\underline{\mathtt{\color{magenta}{Given:↓}}}}}$

A compound contain:

• 5.93% Hydrogen
• 94.07% Oxygen

$\LARGE\bold{\color{lime}{\underline{\mathtt{\color{yellow}{Find:↓}}}}}$

• What is its empirical formula?

$\LARGE\bold{\color{yellow}{\underline{\mathtt{\color{lime}{Solution:↓}}}}}$

Dividing first by the molecular mass you have;

$\bold{For \: oxygen; 94.07 \div 16 =5.879}$

$\bold{For \: hydrogen; 5.93 \div 1= 5.93}$

Dividing by the lowest value:

$5.93 \div 5.879= 1.0086$

$5.879 \div 5.879= 1.00$

$\large \bold \pink{\therefore \: Empirical \: formula = HO}$

$\large\bold\orange{✧══════════•❁❀❁•══════════✧}$

Hopes its helpful