Question

given a is 3, n is 8 , s is 192 find d​

Answer 1

Answer:

sn=n/2[2a+(n-1)d]

192=8/2[2x3+(8-1)d]

192/4+6+7d

6+7d=48

d=42/7

d=6....

Step-by-step explanation:

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Answer 2

$\huge{\underline{\underline{\red{\mathfrak{Answer :}}}}}$

Given :

First term (a) = 3

Number of terms (n) = 8

Sum (Sn) = 192

To Find :

Common Difference (d)

Solution :

We know that,

$\LARGE{\boxed{\blue{\sf{S_{n} = \frac{n}{2} 2a + (n - 1)d}}}}$

(Putting Values)

Sn = 8(2 * 3 + (8 - 1)d)/2

192 = 4(6 + 7d)

192/4 = 6 + 7d

48 = 6 + 7d

48 - 6 = 7d

42 = 7d

42/7 = d

6 = d

$\large{\boxed{\green{\sf{Common \: Difference \: (d) \: = \: 6}}}}$