given a line ABCD in which ab = BC = CD B is (0, 3 )and C is( 1, 8 )find the coordinates of a and d
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Answer:
A = (-1 , -2)
D = (2 , 13)
Step-by-step explanation:
AB = BC = CD
B = (0 , 3) C = ( 1 , 8)
BC = √(1 - 0)² + (8-3)² = √26
Slope = (8-3)/(1 - 0) = 5
y = 5x + c
3 = 0 + c
=> c = 3
y = 5x + 3
(Ax , Ay)
AB = √(Ax - 0)² + (Ay - 3)² = BC
=> √(Ax - 0)² + (Ay - 3)² = √26
=> Ax² + (Ay -3)² = 26
=> Ax² + (5Ax + 3 - 3)² = 26
=> Ax² + 25Ax² = 26
=> 26Ax² = 26
=> Ax² = 1
=> Ax = ±1
Ax = 1 is C
=> Ax = -1
Ay = -2
A = (-1 , -2)
Simialrly
Dx , Dy
(Dx - 1)² + (Dy - 8)² = 26
=> (Dx - 1)² + (5Dx - 5)² = 26
=> (Dx - 1)² = 1
=> Dx - 1 = ±1
=> Dx = 2 , 0
0 is B
=> Dx = 2
Dy = 13
D = (2 , 13)
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