Question

Given a list of cards numbered from 1 to 20. A card is selected at random. What is the probability that the card selected is divisible by both 2 and 3

Answer 1

p (e)=3/20

favourable 6.12.18.=3

total outcomes 20

Answer 2

Answer:

Step-by-step explanation:

Given: There are 20 number cards

that is 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20

To find:P(card which is divisible by both 2&3)

Proof: 6 is the number which has 3&2 as factor

Therefore the number divisible by 6 are 6,12,18

So P(card divisible by 2&3)=3/20