Given a number of capacitors labelled as 8 μF, 250 V. Find the minimum number of capacitors needed to get an
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Answer:
32
Explanation:
Increasing voltage from 250V to 1000V requires arranging 4 capacitors in series but this decreases the C
net
=8/4μF=2μF
Increasing the capacitance to 16μF requires 8 such rows placed in parallel.
Total number of capacitors =8×4=32.
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