Given a soda can with a volume of 15 and a diameter of 2, what is the volume of a cone that fits perfectly inside the soda can? (hint: only enter numerals in the answer bl
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Answered by
19
According to question
Diameter of Can D = 2
Thus
Radius of Can = D/2 = 1
So Volume of Can = pi r^2 * H
15 = pi * H
So Height of Can H = 15 / pi
Now for Cone
Radius r = 1. Height h = 15/pi
So Volume of cone = 1/3 pi r^2 * h
= 1/3 * pi * 1 * 15 /pi
= 5
Thus Volume of cone is 5
Diameter of Can D = 2
Thus
Radius of Can = D/2 = 1
So Volume of Can = pi r^2 * H
15 = pi * H
So Height of Can H = 15 / pi
Now for Cone
Radius r = 1. Height h = 15/pi
So Volume of cone = 1/3 pi r^2 * h
= 1/3 * pi * 1 * 15 /pi
= 5
Thus Volume of cone is 5
Answered by
13
Given:
Volume of soda can= 15
Diameter of soda can and cone (d) =2
Radius of soda can and cone = d/2 = 2/2= 1
Radius of soda can= 1
Volume of soda can(Cylinder) = πr²h
15 = π(1)²h
15 = πh
h = 15/π………….(1)
Volume of cone = ⅓(πr²h)
Volume of cone = ⅓ ×π× 1²×(15/π)
[ From eq. 1]
= 15/3= 5
Hence , volume of cone = 15
HOPE THIS WILL HELP YOU...
Volume of soda can= 15
Diameter of soda can and cone (d) =2
Radius of soda can and cone = d/2 = 2/2= 1
Radius of soda can= 1
Volume of soda can(Cylinder) = πr²h
15 = π(1)²h
15 = πh
h = 15/π………….(1)
Volume of cone = ⅓(πr²h)
Volume of cone = ⅓ ×π× 1²×(15/π)
[ From eq. 1]
= 15/3= 5
Hence , volume of cone = 15
HOPE THIS WILL HELP YOU...
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