Question

Given a trapezium ABCD in which AB||CD.
If angle A = angle B = 50°, what are the measures of angle D and angle C?
​

Answer 1

Answer:

130

Step-by-step explanation:

angle BAD + angle CDA = 180 degrees

(as AB || CD, AD is transversal; sum of co-interioir angles=180 degrees)

similarly, angle ABC+ angle BCD=180 degrees

We know that angle BAD=angle ABC =50 degrees

Therefore from #1 and #2 :angle CDA=angle BCD= 180-50 = 130 degrees