Given a12=37,d=3,find a and s12
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Answer:
a=4 and s12=246
Step-by-step explanation:
Given a12=37
d=3
an=a+(n-1)d
a12=a+(12-1)3
37=a+(11)3
37=a+33
37-33=a
a=4
.'.value of a=4
sn=n/2[2a+(n-1)d]
s12=12/2[2(4)+(12-1)3]
=6[8+(11)3]
=6(8+33)
=6×41
=246
.'. the value of s12=246
HOPE IT HELPS!!!!!
THANK YOU
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