Question

given a12 = 37,d = 3,find a and S12

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Answer 1

Answer:

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Given terms :

• a12 = 37
• d = 3
• n = 12

To find :

• a and S12

Solution :

⟹ a12 = a + 11d

⟹ 37 = a + 11(3)

⟹ 37 = a + 33

⟹ a = 37 - 33

⟹ a = 4

Therefore, the first term (a) is 4.

➙ Sn = n/2 [ 2a + (n - 1)d ]

➡ S12 = 12/2 [ 2(4) + (12 - 1)3 ]

➡ S12 = 6 [ 8 +(11)3 ]

➡ S12 = 6 [ 8 + 33 ]

➡ S12 = 6 [ 41 ]

➡ S12 = 246

Therefore, the sum of 12 terms (S12) is 246.

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Step-by-step explanation:

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Answer 2

Sᴏʟᴜᴛɪᴏɴ:

a12 = a + 11 × 3= 37

⇒ a + 33 = 37

⇒a = 37 - 33

⇒ a = 4

Sn = n/2 [a + l]

⇒ S12 = 12/2 [4 + 37]

⇒ S12 = 6 × 41

⇒ S12 = 246

[ʀᴇғᴇʀ ᴛʜᴇ ᴀᴛᴛᴀᴄʜᴍᴇɴᴛ]