Given a2 + b2 = 1, c2 + d2 = 1, p2 + q2 = 1,
where all numbers are real, then
(1) ab + cd + pq = 1 (2) ab + cd + pq < 3
(3) ab + cd + pq 2 3
(4) ab + cd + pq < 3/2
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Answer:
ab + cd + pq = 1 (2) ab + cd + pq < 3
here is your answer
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