Question

given a²+b²=1, c²+d²=1, p²+q²=1 where all numbers are real then
1)ab+cd+pq=>1
2)ab+cd+pq=>3
3)ab+cd+pq<3
4)ab+cd+pq=<3/2

please explain briefly​

Answer 1

Answer:

Answer is (d). ab+cd+pq =≤3/2

above I've explained why I take sin theta and cos theta there,

and also explained the answer

so I wish my answer is helpful and Brainliest to you.