Math, asked by priyal0123, 20 hours ago

Given: AB = AC ; DB = EC
Prove: ∆DBC = ∆ECB

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Answers

Answered by meetdchaudhari2006

2

Answer:

in DBC and ECB

If AB = AC, then half AC = half AB

AB = AC then angle ABC and Angle ACB are equal

BC = BC (common)

they are congruent

Step-by-step explanation:

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