Question

given ∆ABC~∆PQR,if AB/PQ=1/3,then find ar∆ABC/ar∆PQR

Answer 1

GIVEN:
ΔABC ~ Δ PQR & AB/PQ = 1/3
ar(ΔABC)/ar( Δ PQR )= AB²/ PQ²
[The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.]
ar(ΔABC)/ar( Δ PQR ) = 1²/3²
[Given =AB/PQ = ⅓]
ar(ΔABC)/ar( Δ PQR ) = 1/9
Hence, the Area of ΔABC/Area of ΔPQR = 1/9

HOPE THIS WILL HELP YOU….

Answer 2

Solution :

Given ∆ABC ~ ∆PQR

And

AB/PQ = 1/3 ---( 1 )

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We know that ,

If ratio of the areas of two

similar triangles is equal to

the ratio of the squares of their

corresponding sides .

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Now ,

∆ABC/∆PQR = ( AB/PQ )²

= ( 1/3 )² [ from ( 1 ) ]

= 1/9

= 1 : 9

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