Question

given ΔABC ~ΔPQR, if AB/PQ=1/3,then find arΔABC/arΔPQR.

Answer 1

Heyaa...

Here's your answer..

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We know that area of similar triangles are equal
to the proportion of the squares of proportional
sides...

Thus...ar∆ABC/ar∆PQR=
${AB}^{2} \div {PQ}^{2} = ({1 \div 3})^{2} = 1 \div 9$
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HOPE IT HELPS

@Rêyaañ11

Answer 2

Given:

ABC and PQR are similar triangles.

$\frac{{area}(A B C)}{{area}(P Q R)}=\left(\frac{1}{3}\right)^{2}$

To find:

The ratio of area of triangle ABC and area of triangle PQR

Solution:

The ratio of the areas of two similar triangles is equal to the square of ratios of corresponding sides.

$\frac{{area}(A B C)}{{area}(P Q R)}=\left(\frac{AB}{PQ}\right)^{2}$

$\frac{{area}(A B C)}{{area}(P Q R)}=\frac{1}{9}$

The ratio of area of triangle ABC and triangle PQR is $\frac{1}{9}$.

To learn more...

1. Given triangle ABC ~ triangle PQR AB/PQ =1/3 then find the area of triangle ABC/ triangle PQE

https://brainly.in/question/3098344

2. In triangle ABC,PQ is a line segment intersecting AB at P and AC at Q such that PQllBC and PQ divides triangle ABC into two parts in equal area.Find BP/AB.

brainly.in/question/759156