Question

Given-∆ABC~∆PQR. If AB/PQ=1/3,then find arof∆ABC/∆PQR

Answer 1

As triangle ABC is similar to triangle PQR
By Area Theorem
ar(ABC)/ar(pqr)=(AB/PQ)^2=(BC/QR)^2=(AC/PR)^2
                         =(1/3)^2
                         =1/9    

Answer 2

Ar(abc)/ar(pqr)=(ab/pq)square
Ar(abc)/ar(pqr)=(1/3)square
Ar(abc)/ar(pqr)=1/9


So, we can write
Ar(abc)=1
Ar(pqr)=9