Question

Given an array int marks.[]={99,67,78,56,88,90,34,85} calculate the address of marks [4], if base addressv=1000

Answer 1

Answer:1006

Explanation:

By adding 1000 to 6

Answer 2

Given an array of integers and the stating address of this array, Find the address of data at fourth index.

Explanation:

• Let there be an array of 'N' integers having base address 'x' (that is the address of the first element of the array is 'x').
• Then the address 'A' of nth index out of $0-(N-1)$ indices of the size of each integer data type given to be 'b' bytes is given by,    $A=x+b(n) \ \ \ \ \ \ \ \ \ \ \ \ ->0\leq n \leq (N-1)$
• In general the size of integer data type is considered to be $4\ bytes$. If the size of integer is different the above formula can be used to determine the address.
• Now here we have, $x=1000\ \ \ \ \ \ \ \ \ b=4\ \ \ \ \ \ \ \ \ \ \ n=4$
• Hence the address of marks[4] is,  
•                           $A_4=1000+(4)4\\->A_4=1016$     ---->Answer