Question

Given :
Anil is four times as old as his son. After 16 years , he will be twice as old as his son .
To find :
Find his son’s present age.
Solution :
Let the present age of the son = x years.
Therefore, the present age of his father = 4x years.
So, after 16 years,
Son"s age = (x + 16) and father"s age = (4x + 16) years
According to question:
4x+ 16 = 2(x + 16)
4x + 16 = 2x + 32
Transposing 2x to LHS and 16 to RHS, we get
4x-2x = 32-16
2x= 16
Dividing both sides by 2, we get
= 2x/2
= 16/2
x= 8
So, the present age of the son
= X
= 8 years,
And the present age of the father
= 4x
= 4(8)
= 32 years

Answer 1

Answer:

THE ANSWER IS ALREADY GIVEN

Step-by-step explanation:

x=8

y=32