Question

given are the parellel sides a and b height h.find the area of trapezium a=1.8m b=1.8m h=1.2m​

Answer 1

ABCD is a trapezium.

Draw two perpendiculars from C and D on side AB intersecting AB at points O and N respectively.

∴□ONCD is a rectangle and △AOD & △BNC are triangles.

Also, △AOD≅△BNC

Area of rectangle □ONCD=ON×OD

Area of △AOD =

2

1

×AO×OD

Area of □ABCD = Area (□ONCD) + 2 × Area (△AOD)

=(ON×OD)+2×

2

1

×AO×OD

=

2

OD

[2(ON)+2(AO)]

=

2

h

[(ON+2(AO))+ON]

=

2

h

[AB+CD]

=

2

h

×sum of parallel sides

Answer 2

Answer:

2.16 m²

Step-by-step explanation:

Area = 1/2 x height x (sum of parallel sides)

= 1/2 x 1.2 x (1.8+1.8)

= 2.16

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