Question

Given -
B AND Q are aute angles
sin B = sinQ
TO PROVE -- angle B =angle Q
Soln-- SinB = SinQ
by cancelling sin on both
angle B =angle Q
is it correct plz check my answer​

Answer 1

Step-by-step explanation:

An acute angle is an angle that measures between 90° and 0°

so ,0°<B,Q<90°

sin B = sin Q

sin B - sin Q=0

formula sin A- sin B=2 [cos(A+B)/2]×[sin(A-B)/2]

so ,

2[cos(B+Q)/2][sin(B-Q)/2]=0

[cos(B+Q)/2][sin(B-Q)/2]=0

from this equation we either have case

1<< cos(B+Q)/2=0

or

2<<sin(B+Q)/2=0

from case 1,

(B+Q)/2=90°

B+Q=180°..{ this case is not possible because B and Q are acute angle }

from case 2,

(B-Q)/2=0

B-Q=0

B=Q

Proved

angle B is equal to Q

.... This is the correct way of doing this question you can't directly cancel sin from both side...