Given :
Co³⁺ e⁻ → Co²⁺ ; Eᵒ = 1.81V Pb⁴ + 2e⁻ → Pb²⁺ ; Eᵒ = +1.67 V Ce⁴⁺ + e⁻ → Ce³⁺ ; Eᵒ = +1.61V Bi³⁺ + 3e⁻ → Bi ; Eᵒ = +0.20V Oxidizing power of the species will increase in the order
(A) Ce⁴⁺ < Pb⁴⁺ < Bi³⁺ < Co³⁺ (B) Co³⁺ < Pb⁴⁺ < Ce⁴⁺ < Bi³⁺ (C) Bi³⁺ < Ce⁴⁺ < Pb⁴⁺ < Co³⁺ (D) Co³⁺ < Ce⁴⁺ < Bi³⁺ < Pb⁴⁺
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