Question

given cosec0 = 3/2 . find tan0 and sec0​

Answer 1

Answer:

tanθ = 2/√5 and secθ = 3/ √5

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Step-by-step explanation:

sinθ = 1 / cosecθ

sinθ = 2 / 3

sin^2θ + cos^2θ =1

cos^θ = 1 - 4 / 9

cos^2θ = 9-4 / 9

cos^2θ = 5 / 9

taking square roots on both sides

cosθ = √5 / 3

secθ = 1/ cosθ

secθ = 3 /√5

1 + tan^2θ =sec^2θ

tan^2θ = sec^2θ -1

tan^2θ = 9 / 5 -1

tan^2θ = 9 - 5 / 5

tan^2θ = 4 / 5

taking square roots on both sides

tanθ = 2 /√5