Question

Given cot θ = 17/18

find cos θ and cosec θ​

Answer 1

$cot A = \frac{Adjacent}{0pposite} = \frac{17}{18}$

H → Hypotenuse side

A → Adjacent side

O → Opposite side

$H^2=A^2+O^2\\H=\sqrt{A^2+O^2} \\H=\sqrt{17^2+18^2}\\H=\sqrt{289+324}\\H=\sqrt{613}$

H → Hypotenuse side → $\sqrt{613}$

A → Adjacent side → 17

O → Opposite side →`18

 

$Cos A =\frac{A}{H} =\frac{17}{\sqrt{613} }$

$Cosec A = \frac{H}{O} =\frac{\sqrt{613} }{18}$

HOPE IT HELPS U :-)