.Given E ⁰
(i) Mg 2+ /Mg(s), E 0 = – 2.36
(ii) Ag + /Ag(s), E 0 = 0.80
(iii) Al 3+ /Al(s), E 0 = – 1.66
iv) Cu 2+ /Cu(s), E 0 = 0.52
Out of the above-given elements which is the strongest oxidizing agent and which is the weakest oxidizing agent?
(a) (iv) is strong whereas (ii) is the weakest oxidizing agent
(b) (ii) is the strongest whereas (i) is the weakest oxidizing agent
(c) (i) is the strongest whereas (ii) is the weakest oxidizing agent
(d) (ii) is the strongest whereas (iii) is the weakest oxidizing agent
Answers
Answered by
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Answer:
1+2(6-+8)0(7777777)77777/
Answered by
0
Answer:
Given Zn∣Zn
2+
(0.001M)∣∣Cu
2+
(0.1M)∣Cu
Overall cell reaction:
Zn⟶Zn
2+
+2e
−
Cu
2+
+2e
−
⟶Cu
Zn+Cu
2+
⟶Zn
2+
+Cu
E
cell
o
=standard reduction potential of cathode + standard oxidation potential of anode
E
cell
o
=0.34 to 0.76 V
E
cell
o
=1.1 V
K
C
=
[Cu
2+
]
[Zn
2+
]
=
10
−1
10
−3
=10
−2
EMF of the cell at any electrode concentration is:
E=E
o
−
n
0.059
log(K
C
)=1.1−
2
0.059
log(10
−2
)=1.1−
2
0.059
×(2)=1.1−0.059=1.041V
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