Question

(Given E0Ag+|Ag = 0.80V & E0Cu2+|Cu = 0.34V)

Answer 1

★ Answer

E° Ag+| Ag = 0.80 V

E° Cu+2| Cu = 0.34 V

then cell representation ;

Cu+2| Cu || Ag+| Ag

E° cell = E° cathode - E° anode

= E° Ag+| Ag - E° Cu+2| Cu

= (0.80-0.34) V

= 0.46 V