Question

Given EB=DB AE=BC angle A=angleC =90°SO ∆ABE =∆CDB ​

Answer 1

Answer:

By RHS congruence criterion,

since it is given that

EB=BD, AE=CB, ∠A=∠C=90

o

Hypotenuse and one side of a right angled triangle

are respectively equal to the hypotenuse and one side

of another right angled triangle.

Therefore,

ΔABE≅ΔCDB.