Given EG = 16 and FH = 12, what is the length of one side of the rhombus
Answers
Answered by
1
10 will be ur ans
Answered by
0
Answer:
11.313 unit
Step-by-step explanation:
suppose , EFGH is a rhombus of longer side "a" and shorter side "b"
here EG = DIAGONAL = 16
FH = another diagonal = 12
for diagonal EG ,
so, a^2 +a^2 = 16^2 ( pithagorous's theorem)
so, 2a^2 = 256
so a = (256/2)^0.5 = 11.313 unit [longer side]
for another diagonal FH ,
so, b^2 +b^2 = 12^2 ( pithagorous's theorem)
so, 2b^2 = 144
so b = (144/2)^0.5 = 8.485 unit [shorter side]
Similar questions